My kulp box setup - please check wiring diagram for correctness

[janastas]

Hi All,

So a few weeks back I ordered the Kulp K40D-PB plus another four smart receivers:

https://kulplights.com/product/k40d-pb/

Smart Receiver SRx1 v4.00

Differential Smart Receiver v2

kulplights.com

I currently have the following setup within an ABS enslosure

• S-400-5 70A power supply (http://www.hansonelectronics.com.au/product/power-supply-s-400-5/)
• Power 8 distro board (http://www.hansonelectronics.com.au/product/power8/)
• The K40D-PB
• One smart reciever in the box as well.
• Note that all pixels will be 5V

Pic of setup is as follows:

Updated Box 3.jpg

• janastas
• Mar 10, 2021

I've tested all the smart receiver ports via FPP and the on board test button and everything seems to work fine.

My query is about how best to utilize the power distro board for power injection.
My understanding is that each smart receiver port can handle 1024 pixels? Is that correct?

If so I'm wondering if the below setup on a single port of the smart receiver will work.
The aim is to utlise the power from the smart receiver port for the first 50 pixels then use a power tee that has the positive not connected from the first set of 50 pixels.
The power going to the next 50 and so and and so forth will come from the power distro board.

See the diagram below for what I want to do.

Pixel controller and pixels setup.png

• janastas
• Mar 11, 2021

I'd appreciate and feedback to confirm that the above diagram will work (Note that I've deliberately only put 9 batches of 50 pixels and they will be running at 30% brightness))

 

[AAH]

The wiring to the Power8 is incorrect. The 2 0V connections are in the centre and the 2 5V connections are on the outside.
If you're running at 30% then you can get away with a power injection point every 100 pixels.
There's 6 potential connection spots for power coming from the power supply. Each side of the 3 V+ and V-. As long as you're not pulling more than 30A from any single output you can just run the K40 and receiver direct from the power supply.

 

[janastas]

The wiring to the Power8 is incorrect. The 2 0V connections are in the centre and the 2 5V connections are on the outside.

Yep thanks, the physical wiring is correct on the power8 distro (I double checked it), I just didn't look close enough when I was doing the diagram in MSPaint!

If you're running at 30% then you can get away with a power injection point every 100 pixels.

Gotcha, thanks that will save me having to power inject every 50 pixels.
Just to confirm in the diagram I've specifically called out at the first 50 pixels will be powered by the smart receiver port then the rest of the pixels will be powered by power tees. That wiring all looks correct?

There's 6 potential connection spots for power coming from the power supply. Each side of the 3 V+ and V-. As long as you're not pulling more than 30A from any single output you can just run the K40 and receiver direct from the power supply.

ok thanks. The power8 distro is using 4 of the 6 connection points.

The K40 and receiver will use the other two but just wanted to have one set of cable instead of two coming from the power supply hence the wago lever nuts someone else in the ABS box

 

[i13]

If you can get away with power injection every 100 pixels, you should be able to get away with power injecting in both directions so that no pixel is more than 100 pixels away from an injection point. Data is directional but power isn't. If you connect the positive in both directions at the injection point, you can have an injection point every 200 pixels. All pixels in the run are on the same power supply in your diagram but if they weren't, you'd need to cut the positive line in the pixels half way between the injection points so that you don't connect the power supplies' positive outputs together.

Regardless of whether you're going to inject in both directions or not, if you're planning to have 100 pixels away from the injection point, it would be a good idea to bench test this for voltage drop and incorrect colours. Not all pixels are created equal; the limit will depend on their current draw, the wire thickness and wire length between them. You'll also need to consider that there will be voltage drop in all wires in your diagram. The voltage that reaches the pixels at the injection points will already be below 5V. Keeping the cables short and thick helps.

 

[Jarrad33]

What is the box called you used. Where did you get it from ?

 

[janastas]

What is the box called you used. Where did you get it from ?

This box from Hanson electronics

Box-390x290x160 | Hanson Electronics

ABS box 390x290x160

www.hansonelectronics.com.au

 

[janastas]

Thanks for your feedback all. This all helps a lot and I can now concentrate on power injection for my props but also building more props now.

The last question I had was just around the calcs for the number of pixels I could technically run off this setup.

So for the power supply I have:

SC-400-5-70: 5V 70A 350W
Under the assumption that the max load I'll be applying is 75% = 350W * 75% =~ 260W

5V pixels - watts per pixel at 30% brightness = 5V * 0.06A (60mA) @ 30% = 0.09W per pixel

So 260W / 0.09W = 2,888 pixels in total using this enclosure setup

I haven't taken into consideration the power required to run the K40D-PB or the smart receiver but guessing I could round down to about 2,500 pixels to be safe?

If anything doesn't look right above please let me know.

 

[i13]

You must be using WS2811-compatible pixels because you're using receivers that provide that data type. You can therefore change your calculation to 55.5 mA per pixel. 60 mA is a more realistic value for WS2801 and dumb RGB. In reality, the pixels are likely to draw even less than 55.5 mA at 100% brightness. The exact figure varies but WS2811-compatible pixels can't exceed 55.5 mA.